Home-Wrecking lesbians, and the husbands that should be very afraid spam...

Quote:

Originally posted by Kanzen

@ Hydra: You should call up the station and call the guy out for being a fucktard.

I was yelling at him through the radio. I'm good with that.

Actually it's a pretty big difference. It's ten times as likely that you'll win if you buy 10 tickets!

The exact chance of winning the jackpot would be 1 to 21,026,821,200 if you have one ticket with one set of numbers.

59*58*57*56*55*35 = 21,026,821,200

That turns to 0.000000005% chance.

*Rounded up.

Quote:

Originally posted by King_Daddy

Anyone know me???

Guess not!!! lol

Quote:

Originally posted by King_Daddy

...

Guess not!!! lol

Hey wait....I know you.


I think.

Sorry, Kanzen distracted me with money and math.

Bisexual chicks love math.

Damn Math!

Quote:

Originally posted by Kanzen

The exact chance of winning the jackpot would be 1 to 21,026,821,200 if you have one ticket with one set of numbers.

59*58*57*56*55*35 = 21,026,821,200

That turns to 0.00000000005% chance.

*Rounded up.

I'm not sure what figures you're using to calculate. The Powerball website has it at 1 in 175,223,510 with one ticket.

If it's on the internet it has to be true.

So SP is a stripper now.

Quote:

Originally posted by Kanzen

The exact chance of winning the jackpot would be 1 to 21,026,821,200 if you have one ticket with one set of numbers.

59*58*57*56*55*35 = 21,026,821,200

That turns to 0.000000005% chance.

*Rounded up.

Combinations, not permutations though

Quote:

Originally posted by King_Daddy

Damn Math!

How've you been?

Yeah their math doesn't add up unless you set the bar for a lesser prize. The number pool alone supports my statement. There is a total of 59 available numbers, no repeats. Every time you pull a lone number out it will drop the pool of available numbers. Fifty-nine different numbers for first, 58 numbers for second, 57 for third, 56 for fourth, and then 55 for the last regular set. Then there are 35 numbers available for the powerball. I think they are misleading people to get them to play.

Quote:

Originally posted by EricLindros

...

Combinations, not permutations though

Right because the order does not matter, but how did we get to 1 in 21 billion?

It would be 1 in 21 billion if you had to match all the white balls in te exact order they're drawn in

Technically it isn't a permutation because the order of numbers does not matter. It would be a combination because the numbers don't have to be in order. They always sort smallest to largest with the powerball.

If I pick 56, 43, 22, 7, 23 and the lotto is 7, 22, 23, 43, 56 it would win.

Dear Math,

Grow up and solve your own problems.


Sincerely,

Sugar.

I suppose they might be working with the idea that the lowest number automatically disqualifies any number under it. Which mathematically would be closer to their estimation. Which is probably the way I should of thought about it to begin with. But then the number set causes combination scale to fluctuate wildly.

Quote:

Originally posted by Kanzen

Technically it isn't a permutation because the order of numbers does not matter. It would be a combination because the numbers don't have to be in order. They always sort smallest to largest with the powerball.

If I pick 56, 43, 22, 7, 23 and the lotto is 7, 22, 23, 43, 56 it would win.

Yeah, that's what I'm saying, but you're not doing the math that way.

Instead of (1/59)(1/58)(1/57)(1/56)(1/55)(1/35) = 1 in 21 billion [permutation] it's (5/59)(4/58)(3/57)(2/56)(1/55)(1/35) = 1 in 175 million [combination]

Quote:

Originally posted by Kanzen

Yeah their math doesn't add up unless you set the bar for a lesser prize. The number pool alone supports my statement. There is a total of 59 available numbers, no repeats. Every time you pull a lone number out it will drop the pool of available numbers. Fifty-nine different numbers for first, 58 numbers for second, 57 for third, 56 for fourth, and then 55 for the last regular set. Then there are 35 numbers available for the powerball. I think they are misleading people to get them to play.

I don't think this method of calculation applies because there's not a separate ticket and drawing for each number. I think it's just all combinations using 5 out of 59 and 1 out of 35.


edit: or what EL said.

Quote:

Originally posted by Kanzen

Technically it isn't a permutation because the order of numbers does not matter. It would be a combination because the numbers don't have to be in order. They always sort smallest to largest with the powerball.

If I pick 56, 43, 22, 7, 23 and the lotto is 7, 22, 23, 43, 56 it would win.

Also, gonna play those numbers now just to make you share the jackpot.